5. An electron is separated from a proton by a distance of 1.00 10^-10 m. What is the magnitude of the electric force between them?​

2.304 * 10^-10N

Explanation:

The magnitude of the force is expressed as;

F = kq1q2/r²

k is the coulomb constant

q1 id the charge on the electron = -1.6*10^-19C

q2 is the charge on the proton = 1.6*10^-19C

k = 9*10^9

Substitute

F  = (9*10^9)*( -1.6*10^-19)( 1.6*10^-19)/(1.00 10^-10)^2

F = 9*10^9*-2.56*10^-38/1.00 10^-20

F = -23.04*10^-29/1.00 10^-20

F = -23.04 * 10^(-29+20)

F = -23.04 * 10 ^-9

F = -2.304 * 10 ^ -10N

Hence the magnitude of the electric force between them is

2.304 * 10^-10N

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.

the ima (higher than 1m) will be greater than the ima with the height of 1m.