a 2.00x10^2 -g sample of water at 60 C is heated yo water vapor at 140 C. How much thermal energy is absorbed

The thermal energy absorbed is 66.98 kJ.

Explanation:

The thermal energy absorbed can be found by using the following equation:

Where:

Q: is the thermal energy =?

m: is the mass of water = 2.00x10² g

ΔT = T₂ - T₁ = 140 °C - 60 °C = 80 °C

C: is the specific heat of water = 4.186 J/(°C*g)

Hence, the thermal energy absorbed is:  

Therefore, the thermal energy absorbed is 66.98 kJ.

I hope it helps you!    

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