What is the frequency of a wave if the wavelength is 567 m and the velocity is 23,000 m/s?

40.56Hertz

Explanation:

v=f×lamda( I don't have the symbol)

from the question,

v=23,000

f=?

lamda i.e wavelength=567m

therefore, 23000=f×567

divide by 567

23000/567=567f/567

40.56 Hz=f

so, f=40.56Hz

i think the answer would be b

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west