A man with a weight of 450 N climbs a ladder to a height of 5.2 meters. How much work did he do?​

A force of 25.0 Newtons is applied so as to move a 5.0 kg mass a distance of 20.0 meters. How much work was done?

Ans. W = F × d = 25 N × 20.0 m = 50 J

Explanation:

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the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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