The ancient fish fossils were dated using C-14. If 1/16 the original amount of C-14 remains in the skeletons, approximately how old are the fish. The half-life of C-14 is 5730. a) 11,460 years
b) 17,190 years
c) 22,920 years
d) 28,650 years​

c) 22,920 years

Explanation:

The half-life of C-14 is 5730 so in 5730 years , amount of C-14 is reduced to half.

In 5730 x 2  years , the amount of C-14 is reduced to 1/4 .

In 5730 x 3 years ,  the amount of C-14 is reduced to 1/8 .

In 5730 x 4 years ,  the amount of C-14 is reduced to 1/16 .

In 22920 years ,  the amount of C-14 is reduced to 1/16 .

So the answer is 22920 years.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.