The image below shows how wolves and dogs compare to some other animals in the levels of classification. Animalia Insect Fish Rabbit Fox Jackal Wolf Dog Chordata Fish Rabbit Gat Fox Jackal Wolf Dog Mammalia Rabbit Cat Fox Jackal WOLF Dog Camivora Cat Fox Jackal Wolf Dog Canidae FOX Jackal Wolf Dog Canis Jackal Wolf Dog Canis lupus Wolf Dog Based on the chart, how are fish and dogs related? (5 points) A They belong to the same kingdom but different phyla. B They belong to the same phylum but different classes. C They belong to the same kingdom and class. D They belong to the same phylum and dass.​

Apiano tuner uses a tuner to create a tone of 5.00 x 10² hz. when a key on the piano is struck he hears 5 beats per second. what is a possible frequency of vibration for the piano string? 2500 hz 1300 hz 605 hz 495 hz

Aroll in a paper machine is powered by a separately excited dc machine. operating point 1 (under load): the roll typically operates at 764 rpm and must provide 301 nm of torque to oppose the load of the paper. the armature voltage is 230v for this operating point operating point 2 (no load): when the load is removed the speed of the roll increases to 900 rpm (the field characteristics are unchanged) la ea dev m (a) calculate the maximum torque (units of nm) that the motor can supply with this applied voltage (b) calculate the value of the armature resistance, ra (in ohms) (c) at operating point 1 (loaded condition), the field current, i, and the total input power (armature field), are measured to be to be 10 a and 28,600 w respectively. use this information to calculate the value of the field resistance, rf (in ohms). (d) (d) at operating point 1 (loaded condition), calculate the motor efficiency. express your answer as a percent to at least 2 significant digits. (d) if the field voltage is reduced by 1/2, calculate the new stall torque (in nm) of the motor (f). if the field voltage is reduced by 1/2, calculate the new no-load speed (in rad/sec)

A1,700kg car is being used to give a 1,400kg car a push start by exerting a force of 140n the impulse on the smaller car during the 30.0s of contact is +670kg*m/s. what is the impulse of the smaller car on the larger car? -814 kg*m/s 0kg *m/s -670kg*m/s -550kg*m/s