Physics, 10.03.2021 08:50 chonawilson4

A rocket is launched vertically and returns its launch point in 7 seconds. a. What us it’s launch velocity?
b. How high did it go?
C. What is its velocity right before it hits ground?

Answers: 3

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Answers

Answer from: alexsrules9711

A. 35 m/s

B. 61.25 m

C. 35 m/s

Explanation:

From the question given above, the following data were obtained:

Time of flight (T) = 7 s

Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:

Time of flight (T) = 7 s

Time (t) take to reach maximum height =?

T = 2t

7 = 2t

Divide both side by 2

t = 7/2

t = 3.5 s

A. Determination of the Lauch velocity.

Time (t) to reach maximum height = 3.5 s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

v = u – gt (since the rocket is going against gravity)

0 = u – (10 × 3.5)

0 = u – 35

Collect like terms

0 + 35 = u

u = 35 m/s

Thus, the Lauch velocity is 35 m/s

B. Determination of maximum height reached by the rocket.

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) = 35 m/s

Maximum height (h) =?

v² = u² – 2gh (since the rocket is going against gravity)

0² = 35² – (2 × 10 × h)

0 = 1225 – 20h

Rearrange

20h = 1225

Divide both side by 20

h = 1225 / 20

h = 61.25 m

Thus, the maximum height reached by the rocket is 61.25 m

C. Determination of the velocity before hitting ground.

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 10 m/s²

Time (t) to reach the ground from the maximum height = 3.5 s

Final velocity (v) =?

v = u + gt (since the rocket is moving towards gravity)

v = 0 + (3.5 × 10)

v = 0 + 35

v = 35 m/s

Thus, the velocity of the rocket before hitting ground is 35 m/s

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

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A rocket is launched vertically and returns its launch point in 7 seconds. a. What us it’s launch v...