What is the net force on a dragster with a mass of 900 kg if its acceleration is 32.0 m\s?

Taking into account the Newton's second law, the net force on the dragster is 28800 N.

First you have to know that Newton's Second Law, also called the Fundamental Law of Dynamics, indicates that: "The change in motion is directly proportional to the printed motive force and occurs according to a straight line along which that force is printed."

This means that the acceleration of a moving object depends on the amount of force applied to it at a given moment, in order to modify its trajectory or speed.

Mathematically, Newton's second law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object and is expressed as:

F= m×a

where:

In this case, you know:

Replacing:

F= 900 kg× 32 m/s²

Solving:

F= 28800 N

In summary, the net force on the dragster is 28800 N.

Learn more about the Newton's second law:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards