A toy rocket is launched with an initial velocity of 12.0 m/s in the horizontal direction from the roof of a 30.0-m-tall building. The rocket’s engine produces a horizontal acceleration of \left(1.60 m / s^{3}\right) t, in the same direction as the initial velocity, but in the vertical direction the acceleration is g , down-ward. Ignore air resistance. What horizontal distance does the rocket travel before reaching the ground?

Solution :

The motion in the y direction.

The time taken by the toy rocket to hit the ground,

S = distance travelled = 30 m

u = 0 m/s

a =

t= time in seconds

Therefore,

t = 2.47 sec

Now motion in the x direction,

u = 12 m/sec

Upon integration 'v' with respect to 't'

Once again integrating with respect to t,

  = 0.0176+29.64

   = 29.65 m

Therefore, the toy rocket will hit the ground at 29.65 m from the building.

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.