A vehicle is traveling at 60 mph on a level two-lane road with a horizontal curvewith a radius of 1000feet. The pavement has a wet coefficient of friction of 0.30. Each lane is 12 feet wide and there is an 8foot shoulder on both sides of the road. Calculate the minimum distance that should be cleared from the edge of the shoulder if the central angle of the curve equals 35.76 degrees for the vehicle to safely stop in an emergency situation. Use the AASHTOdesign values for stopping sight distance.

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!

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d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form