An object accelerates at 6 m/s2. If the net force acting on the object doubles, what is the new acceleration?
O 3 m/s2
O 12 m/s2
18 m/s2
2 m/s2

12 m/s²

Explanation:

We have Newton's 2nd Law of Motion:

Mass m is in kg and acceleration a is in m/s²

Our 1st acceleration given to us is a = 6 m/s². Let's substitute it into Newton's 2nd Law of Motion:

We are told that the net force doubles, meaning that the new force is 2F:

Mass doesn't change in this system; it is held constant due to Newton's 2nd Law of Motion. Therefore, to increase the net force acted on the object, the acceleration must change.

Since we are doubling the net force and mass stays constant, then acceleration also must double.

Therefore, our answer is (6 m/s²) · 2 = 12 m/s².

12 m/s²

Explanation:

We have Newton's 2nd Law of Motion:

F = ma (Force is equal to [constant] mass times acceleration)

Mass m is in kg and acceleration a is in m/s²

Our 1st acceleration given to us is a = 6 m/s². Let's substitute it into Newton's 2nd Law of Motion:

F = m(6 m/s²)

We are told that the net force doubles, meaning that the new force is 2F:

2F = ma

Mass doesn't change in this system; it is held constant due to Newton's 2nd Law of Motion. Therefore, to increase the net force acted on the object, the acceleration must change.

Since we are doubling the net force and mass stays constant, then acceleration also must double.

Therefore, our answer is (6 m/s²) · 2 = 12 m/s².

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer