Figure 6.26 shows a flywheel of mass 12 kg and radius 50 cm with a rope wrapped around it. On the end of the rope is a
2.0 kg load. Initially it is at rest.
a) Calculate the torque on the flywheel. Assume g to be
9.8 m/s.
b) Work out what its angular momentum will be after 2.5 s.
Angular momentum is a vector and so will have a direction. You
can use the right-hand rule to show its direction.​

Could someone me find the answer to this problem.

Asheet of steel 1.5 mm thick has nitrogen atmospheres on both sides at 1200oc and is permitted to achieve a steady-state diffusion condition. the diffusion coefficient for nitrogen in steel at this temperature is 6 x 10- 11 m2 /s, and the diffusion flux is found to be 1.2 x 10-7 kg/m2 -s. also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is 4 kg/m3 . how far into the sheet from this high-pressure side will the concentration be 2.0 kg/m3 ? assume a linear concentration profile.

Increasing the pressure on one spot of a fluid will increase the pressure everywhere else in the fluid a. pascals principal b. archimedes' principal c. bernoulli's principal