The figure below shows the head of a patient being fixed to a Russell Traction System, where the patient is laying down on his back on a bed that is inclined by 20o with the horizontal as shown. The static frictional force between the patient and the bed is 190N and the coefficient of static friction is 0.4. (a) Find the weight of the patient.
(b) Find the minimum balancing mass, M that stretches the patient from upwards

1.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the mass defect of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev 2.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the binding energy of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev 3.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the binding energy per nucleon of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev