A ray of light has a wavelength 433 nm in water (n = 1.33). What
is its wavelength in a vacuum?
(Remember, the wavelength is longer in
a vacuum.)
(Unit = nm)

The wavelength of the light in a vacuum is 575.89 nm

Explanation:

The given parameter in the are;

The wavelength of the ray of light in water, λ₁ = 433 nm

The refractive index of water, n₁ = 1.33

The relationship between wavelength, λ, and refractive index, 'n', is presented as follows;

λ₁·n₁ = λ₂·n₂

Where;

λ₁ and λ₂ are the wavelength of the wave within  the two mediums

n₁ and n₂ are the respective refractive indices of the mediums

The refractive index of vacuum, n₂ = 1

Let λ₂ represent the wavelength of light in vacuum

Therefore, we have;

1.33 × 433 nm = 1 × λ₂

∴ λ₂ = 1.33 × 433 nm/1 = 575.89 nm

Therefore, the wavelength in a vacuum, λ₂ = 575.89 nm

d they tend to lose electrons and become cations.

explanation:

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