When a 2kg metal is exposed to 2MJ of heat it dissolves into liquid at 500K
Calculate the latent heat of fusion for
the metal. Betty went in to get you metal is exposed to to megajoules of heat ​

1×10⁶ J/Kg

Explanation:

From the question given above, the following data were obtained:

Mass (m) of metal = 2 Kg

Heat (Q) = 2 MJ

Latent heat of Fusion (Hf) =?

Next, we shall convert 2 MJ to J. This can be obtained as follow:

1 MJ = 1×10⁶ J

Therefore,

2 MJ = 2 MJ × 1×10⁶ J / 1 MJ

2 MJ = 2×10⁶ J

Finally, we shall determine the latent heat of fusion. This can be obtained as follow:

Mass (m) of metal = 2 Kg

Heat (Q) = 2×10⁶ J

Latent heat of Fusion (Hf) =?

Q = m•Hf

2×10⁶ = 2 × Hf

Divide both side by 2

Hf = 2×10⁶ / 2

Hf = 1×10⁶ J/Kg

Thus, the latent heat of fusion for the metal is 1×10⁶ J/Kg

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up