6. A car experiences a forward engine force of 2000N. The combined frictional forces acting on the car are 600 N. If the car is accelerating at 3.0m/s, what is the mass of the car?
Ans: 467 kg
(I need the equation and work of it!!!)

467kg

Explanation:

resultant force=2000-600=1400N

F=mass*acceleration

1400=m*3

m=467kg

Hope this can help you.

the answer is 3.1 his answer is wrong mines is right

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.