Please guys help me with this question.​

(a) 150 N

(b) 15.62 N

(c) 8.54 N

(d) 50 N

Explanation:

From the question above,

(a) F' = F₂-F₁

Where F' = Result force, F₁ = 50 N, F₂ = 200 N

Therefore,

F' = 200-50

F' = 150 N

(b) F' = √(F₁²+F₂²)

Where F₁ = 10 N, F₂ =12 N

F' = √(10²+12²)

F' = √(100+144)

F '= √(244)

F =15.62 N

(c)

F' = √[(F₁+F₂)²+F₃²]

Where F₁ = 6 N, F₂ = 2 N, F₃ = 3 N.

Therefore,

F' = √[(6+2)²+3²)

F' = √(8²+3²)

F' = √(64+9)

F' = √(73)

F' = 8.54 N.

(d)

F' = √[(F₁+F₂)²+(F₃+F₄)²]

Where F₁ = 20 N, F₂ = 10 N, F₃ = 20 N, F₄ = 20 N

F' = √[(20+10)²+(20+20)²]

F' = √[(30)²+(40)²]

F' = √[900+1600]

F' = √[2500]

F' = 50 N

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.