If stretching a spring constant of

5.71 N/m

Explanation:

From the question given above, the following data were obtained:

Extention (e) = 3.5 m

Force (F) = 20 N

Spring constant (K) =?

From Hooke's law,

F = Ke

Where :

F => is the force applied

e => is the extention caused by the force

K => is the spring constant

With the above formula, we can obtain the spring constant of the spring as follow:

Extention (e) = 3.5 m

Force (F) = 20 N

Spring constant (K) =?

F = Ke

20 = K × 3.5

Divide both side by 3.5

K = 20 / 3.5

K = 5.71 N/m

Thus, the spring constant of the spring is 5.71 N/m

explanation:

wheres the pic