Suppose you have a 34.9 m length of copper wire. If the wire is wrapped into a solenoid 0.240 m long and having a radius of 0.0510 m, how strong is the resulting magnetic field in its center when the current is 11.0 A?

the strength of the magnetic field inside the solenoid is 6.278 x 10⁻³ T.

Explanation:

Given;

length of the wire, = 34.9 m

length of solenoid, L = 0.24 m

radius of the solenoid, r = 0.051 m

current in the solenoid, I = 11.0 A

The number of turns of the wire is calculated as follow;

The strength of the magnetic field inside the solenoid is calculated as follows;

Therefore, the strength of the magnetic field inside the solenoid is 6.278 x 10⁻³ T.