What is the electric field around a 1 x 10^-9 Coulomb charge at 2 m, when no other charges are present?

the force on the thing and the distance the force moves the thing

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

explanation:

wheres the pic

magnets not strong enough

explanation: