Given: Initial velocity (u)=20 km/h
=5.55m/s
Final velocity (v)=30 km/ h
=8.33 m/s
Time=10seconds
FORMULA TO BE USED
a=v-u/t
=8.33-5.55/10
=0.278 m/s^2
therefore, its acceleration is 0.278m/s^2​

Why does the equilibrium position of the spring change when a mass is added to the spring? will the mass oscillate around the new equilibrium position of the spring or the previous position without a mass attached to the spring? if the equilibrium position of the spring changes by 20 cm (assuming no initial mass) when a mass is added to the spring with constant 4.9 kg/s^2, what is the mass of the object attached to the spring?