A basketball is dropped from top of the rim. It takes 1.3s to fall, what is the displacement? a. 8.45 m
b. 8.321 m
c. 33.67 m
d. 33.8 m

d = 8.45 m

Explanation:

Given that,

A basketball is dropped from top of the rim.

It takes 1.3s to fall.

We need to find the displacement of the basketball. Let the displacement is d. Using second equation of kinematics,

Where

u is the initial velocity, u = 0

a = g

So,

So, the displacement of the basketball is 8.45 m.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

it is b. absorbs thermal energy