Suppose A=B^nC^m, where A has dimensions, LT, B has dimensions L^2T^-1 and C has dimensions LT^2. Determine the dimensions of n and m values.

n = 1/5 and m = 3/5

Explanation:

The given quantity is :

Where

The dimension of [A] = [LT]

The dimension of [B] = [L²T⁻¹]

The dimension of [C] = [LT²]

We need to find the dimensions of n and m values.

Using dimensional analysis,

Comparing both sides,

2n+m=1 ....(1)

-n+2m=1 ,.....(2)

Solving (1) and (2), we get :

n = 1/5 and m = 3/5

Hence, this is the required solution.

answer: its c lololo

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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