2 only If two equal charges each 1C were separated in air by distance of 1km, what would be the force
ween them
r= 1km
a =10

its a 5.5 n

glad that

that the claims meet official rules.

don't misinterpret the claims

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.