Una nave espacial avanza en el espacio libre con una aceleracion constante de 9.0 m/s2. Si parte del reposo diga: ¿Que tiempo tardara en adquirir una rapidez igual a la decima parte de la rapidez de la luz ( c = 3.0 x 108 m/s)?

the results is a decrease in air temperature with an increase of altitude.

explanation:

3.2x10^7

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.