It is the same distance from second base to first base, and from second base to third base. the angle formed by first base, second base, and home plate has the same measure as the angle formed by third base, second base, and home plate. what can you conclude about the distance from first base to home plate, and from home plate to third base? explain.

The answer is

Converting this into a geometry problem requires us to name the points. Let give the home plate a symbol A, first base will be B, second base will be C, and the third base will be D. Now, we can present a geometrical proof:

STATEMENTS | REASONS

(1) BC = CD | Given

m(2) AC = AC | Reflexive Property

(3) triangle ACD = triangle ACB | SAS Congruence

(4) AD = AB | CPCTC

when  CPCTC means Congruent Parts of Congruent Triangles are Congruent.

Therefore, the distance from first base to home plate, and from home plate to third plate are equal.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

answeralert drivers who drift off the road;