Two crates, of mass 75kg and 110 kg are in contact and at rest on a horizontal surface. a 730 n force is exerted on a 75kg crate. if the coefficient of kinetic friction is 0.15, calculate (a) the acceleration of the system and (b) the force that each crate exerts on the other.

Friction force = µ * mass * g 

Friction force of 75 kg = 0.15 * 75 * 9.8 = 110.25 

Friction force = 0.15 * 110 * 9.8 = 161.7 

(a) the acceleration of the system: 

Total force = total mass * acceleration 

Total force = 730 – (110.25 + 131.7) 

730 – (110.25 + 131.7) = 185 * acceleration 

Acceleration = [730 – (110.25 + 131.7)] ÷ (75 + 110) = 2.638 m/s^2 

The force that the 75 kg crate exerts on the 110 kg crate causes the 110 kg
crate to accelerate at 2.638 m/s^2. 

Force = 75 * 2.638 = 197.85 N 

Newton’s 3rd Law: Every action has an equal action in opposite direction!! 

The force that the 110 kg crate exerts on the 75 kg crate = 197.85 N in the opposite direction. 

If the force that the 110 kg crate exerts on the 75 kg crate is +197.85 N, the force that the 75 kg crate exerts on the 110 kg crate is -197.85 N.

Ithink the answer is a

You will hear a hissing sound because of the carbon dioxide escaping the can or bottle