A40.0 kg crate is being lowered by means of a rope. its downward acceleration is 3.80 m/s2. what is the force exerted by the rope on the crate? a 40.0 kg crate is being lowered by means of a rope. its downward acceleration is 3.80 m/s2. what is the force exerted by the rope on the crate?

Newton's Second Law of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:

F = ma =40.0 kg (- 3.80 m/s^2) = -152 J

NOTE: It has a negative sign due to the direction of acceleration.
Hope this answers the question. Have a nice day.