A hockey puck of mass m is moving in the +x-direction at speed vP1 on a frictionless, horizontal surface. It collides with a stone of mass 2m that is initially at rest. After the collision the hockey puck is moving at an angle θ measured from the +x-direction toward the +y-direction and the stone is moving at the same angle θ but measured from the +x-direction toward the −y-direction. In order for the y-component of momentum to be conserved, what must be the ratio of the final speed vS2 of the stone to the final speed vP2 of the hockey puck?

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction 

  soil is  vegetal. in forest or prairies, as well as agricultural fields, dead plants are transformed by different kinds of living organisms.