Con qué velocidad inicial debe lanzarse un objeto directamente hacia arriba para que su altura máxima sea 25 m?

v₀ = 22.1 m / s

Explanation:

This is an exercise in kinetics, let's set a vertical reference system with the positive direction up.

          v² = v₀² - 2 g (y-y₀)

the final velocity at the highest point is zero and as it leaves the floor the initial height is zero

          0 = v₀² - 2gy

         v₀ =

let's calculate

        v₀ =

        v₀ = 22.1 m / s

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

c. magnitude and direction