3. A beam of light passes through the air (n=1.00) and enters a diamond (n=2.42) at an angle of incidence of 40 degrees. Use Snell’s Law to find the angle of refraction in the diamond. If the diamond is placed in a tank of water (n=1.33) and the beam of light enters the diamond at the same angle of incidence, what would be the new angle of refraction? Show all work.

(a) θ₂ = 15.4°

(b) θ₂ = 28.9°

Explanation:

Snell's Law can be written as follows:

where,

n₁ = incident index

n₂ = refracted index

θ₁ = Angle of incidence

θ₂ = Angle of refraction

(a)

n₁ = incident index = 1

 n₂ = refracted index = 2.42

θ₁ = Angle of incidence = 40°

θ₂ = Angle of refraction = ?

Therefore,

θ₂ = 15.4°

(b)

n₁ = incident index = 1

n₂ = refracted index = 1.33

θ₁ = Angle of incidence = 40°

θ₂ = Angle of refraction = ?

Therefore,

θ₂ = 28.9°

12000j is work done

no

explanation:

no i dont know how to solve this you should probably try to google the answer