A 7.0 kg bowling ball moves at 2.45 m/s. How fast must a 2.60 g ping pong ball move so that the two balls have the same kinetic energy

127.12 m/s

Explanation:

From the question,

Kinetic energy of the bowling ball = Kinetic energy of the ping pong ball

1/2mv² = 1/2m'v'²

Where m = mass of the bowling ball, v = velocity of the bowling ball, m' = mass of the ping pong ball v' = velocity of the ping pong ball

make v' the subject of the equation

v' = √(mv²/m') Equation 2

Given: m = 7.0 kg, v = 2.45 m/s, m' = 2.60 g = 0.0026 kg

Subtitute into equation 2

v' = √[(7×2.45²)/0.0026]

v' = √16160.57

v' = 127.12 m/s

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.