Aball is thrown at an angle of 25 degrees to the horizon. the ball has a horizontal velocity component of 12.5 m/s. find the vertical velocity component of the ball and the magnitude of the actual velocity. how high would the ball travel before it begins to come down again?

Horizontal velocity is 12.5m/s

Magnitude of actual velocity we find like this:
cos25*Vm=12,5
Vm = 12,5/cos25
Vm= 13.8m/s

vertical velocity is:
Vv = Vm*sin25 = 5.83m/s

Time after ball will stop ascending is:
t=Vv/a = 5,83/9.81 = 0.59s

Finally we calculate traveled distance:
S=t*Vh = 0.59*12,5 = 7.42m

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