Awaitperson pushes the bottom of a glass tumbler full of water across a tabletop at a constant speed. the tumbler and its contents have a mass of 0.70kg, and the coefficient of kinetic friction for the surfaces in contact is 0.41. what force does the waitperson exert on the glass?

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 Constant speed, therefore net force in the x direction must = 0. 

Find normal foce: 

Fnet in the y direction is equal to 0. 

0 = Fn - Fg 
Fn = 0.70 (9.81) 
Fn = 6.867 N 

x direction: 

Fnet = Fapp - Ff 
0 = Fapp - mu(Fn) 
Fapp = 0.41(6.867) 
Fapp = 2.81547 N

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