At which position will the bar magnets most likely experience the least magnetic potential energy between them? A diagram is shown of 4 different positions for a pair of magnets. A table shows 4 arrangements of a pair of magnets. In the first row, position 1, shows two horizontally oriented magnets as rectangles with the left end in red labeled N and the right end in blue labeled S. A large gap exists between the magnets. The second row, position 2, shows the magnets slightly closer together. In the third row, position 3, they are even closer. In the fourth row, position 4, the magnets are connected, with the blue end of the left magnet connected to the red left side of the magnet to the right.
A. position 1
B. position 2
C. position 3
D. position 4

a. position one

Explanation:

Because when you sit them done the other positions connect automatedly ,but this one does not because to for away.

hope this helps.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

electric field is a function of 1/r^2

yes, the force per unit charge for a point charge is inverse square law.