A negative 6 mC charge enters a region of 45 T magnetic field that is directed up. If the charge is moving toward the south with a speed of 400 m/s

Question: A negative 6 mC charge enters a region of 45 T magnetic field that is directed up. If the charge is moving toward the south with a speed of 400 m/s. determine the magnitude and  direction of the force

Magitude of F = 108 N

Direction: Perpendicular to the plane containing v and B.

Explanation:

From the question,

Since the velocity of the charge(v), is parallel to the field(B).

Therefore, We apply

F = qvBEquation 1

Where F = Force, B = magnetic field, v = velocity, q = Charge.

Given: q = 6 mC = 0.006 C, v = 400 m/s, B = 45 T

Substitute these values into equation 1

F = 0.006×400×45

F = 108 N.

The direction of the force is always perpendicular to the plane containing v and B.

c. magnitude and direction

truck y has a greater velocity than truck x.