A920 kg block is pushed on the slope of a 30
frictionless inclined plane to give it an initial
speed of 50 cm/s along the slope when the block is 2.3 m from the bottom of the incline.
the acceleration of gravity is 9.8 m/s2 . what is the speed of the block at the bot-
tom of the plane?
answer in units of m/s

Using the kinetic energy theorem, we have:
sumW = 1/2 mV²final  - 1/2mV²initial
sumW=mgh, where h=sin30 x AB, AB= 2.3m
50 cm/s=0.5m/s

so 2gsin30 AB =  V²final  - V²initial and  V final = sqrt(2gsin30 AB + V²initial)
  
finally v= 4.77m/s

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.