An electron of kinetic energy 1.59 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 35.4 cm. Find (a) the electron's speed, (b) the magnetic field magnitude, (c) the circling frequency, and (d) the period of the motion.

a)

b)

c)

d)

Explanation:

a) We can find the electron's speed by knowing the kinetic energy:

Where:    

K: is the kinetic energy = 1.59 keV

m: is the electron's mass = 9.11x10⁻³¹ kg

v: is the speed =?

b) The electron's speed can be found by using Lorentz's equation:

  (1)

Where:

F: is the magnetic force

q: is the electron's charge = 1.6x10⁻¹⁹ C

θ: is the angle between the speed of the electron and the magnetic field = 90°

The magnetic force is also equal to:

  (2)

By equating equation (2) with (1) and by solving for B, we have:

c) The circling frequency is:

Where:

T: is the period = 2π/ω

ω: is the angular speed = v/r

d) The period of the motion is:

I hope it helps you!

answer: cesare beccaria developed the classical school of criminology with from philosopher jeremy bentham

explanation:

i will answer your question if you answer mine