The density of liquid oxygen at its boiling point is 1.14 \rm{kg/l} , and its heat of vaporization is 213 \rm{kj/kg} .

how much energy in joules would be absorbed by 3.0 l of liquid oxygen as it vaporized?

M = rho x Vwhere rho is the density of liquid oxygen, V volumem= 1.14 kg/L x 3 L = 3.42 kg
Energy = m  times heat of vaporization Energy = 3.42 kg x 213 kJ/kgEnergy = 724.46 kJ

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.