Physics, 29.08.2019 17:30 20calzoy

The gibson family have bought tickets to the christmas market. there are 4 mothers, 2 grand-mothers and 4 daughters. what is the minimum number of tickets they need?

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The minimum number of tickets that could admit all of them is six (6).

This thing is impossible to explain in words, so I shall attempt it with a diagram:

Here are the six ladies:

   ( A ) ( B )
      |    |
      |    |
   ( C ) ( D )
      |       |
    |       |
   ( E ) ( F )

-- 'E' and 'F' are the daughters of 'C' and 'D' .

-- 'C' and 'D' are the daughters of 'A' and 'B' .

So look what we have now:

-- 'A' and 'B' are the mothers of 'C' and 'D' .
   There's 2 of the mothers.

-- 'C' and 'D' are the mothers of 'E' and 'F' .
   There's the OTHER 2 mothers.

-- 'A' and 'B' are the grandmothers of 'E' and 'F' .
    There's the 2 grandmothers.

-- 'E' and 'F' are the daughters of 'C' and 'D' .
   There's 2 of the daughters.

-- 'C' and 'D' are the daughters of 'A' and 'B' .
   There's the OTHER 2 daughters.

You want to know what ? !
The group is even bigger than THAT.
There are also 2 GRAND-daughters in the family ... 'E' and 'F' .

So now you have a list of 12 people ! ... 4 mothers, 2 grandmothers,
4 daughters, and 2 grand-daughters ... and they all get in to the
Christmas Market with only six tickets. Legally !

Such a deal !

Don't forget : Christmas this year is also the first day of Chanukah !
   All for the same price !

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d.wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current.

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The gibson family have bought tickets to the christmas market. there are 4 mothers, 2 grand-mothers...

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