Astone is thrown straight downward with a speed of 20 m/s from the top of a tall building. if the stone strikes the ground 3.0 seconds later, about how tall is the building?
a) 45m
b) 60m (wrong)
c) 90m
d) 105 m

Do you remember this formula for the distance traveled while accelerated ?

Distance = (initial speed) x (t)  plus  (1/2) x (acceleration) x (t²)

I think this is exactly what we need for this problem.

initial speed = 20 m/s down
acceleration = 9.81 m/s² down
t = 3.0 seconds

Distance down = (20) x (3)  plus  (1/2) x (9.81) x (3)²

Distance = (60)  plus  (4.905) x (9)

Distance = (60)  plus  (44.145)  =  104.145 meters

Choice  D)  is the closest one.

A) acceleration. this seems to be the one that makes sense.