What is the gravitational force acting on a 70.0 kg object standing on the earth's surface ?

G( gravitational acceleration)=-9.81 m/s^2
m(mass) = 70.0 kg

According to Newton's second law of motion:

"F=ma"

Force is equal mass per acceleration therefore

W=mg
This is because weigth is the force of gravity acting in a body and "a" is replaced by "g" because "g"
is gravitational acceleration

Therefore:

W= mg
W= (70.0 kg) (-9.81m/s^2)
W= -686.7 N

* The "N" means newton which is (kg* m/s^2)

Ithink the answer would be a