A1000.–kilogram car traveling 20.0 meters per second east experiences an impulse of 2000. newton • seconds west. what is the final velocity of the car after the impulse has been applied?
(1)18.0 m/s east
(2)19.5 m/s east
(3)20.5 m/s west
(4)22.0 m/s west

So the formula is equal to

M1v1 + I = m2v2

Where m is the mass of the object

V is the velocity of the object

I is the impulse applied

(1000 kg) (20 m/s) – 2000 = m2v2

20000 – 2000 = m2v2

18000 = m2v2

Since the car did change its mass, m1 = m2

18000 = (1000)v2

V2 = 18 m/s east 

The Final velocity ( V₂ ) of the car after the impulse has been applied is ; ( A ;  18.0 m/s east

Given data :

Mass of car = 1000 kg

Initial velocity of car = 20.0 m/s  east

Impulse experienced by car = 2000 N.s  west

V₂ ( final velocity ) after impulse is applied = ?

To determine the final velocity Apply the formula below

M₁V₁  +  Impulse = M₂V₂   ( 1 )   note : M₁ = M₂

since Impulse is applied in opposite direction to the movement of the car  

Equation ( 1 ) becomes

1000 ( 20 ) - 2000 = 1000 ( V₂ )

∴ V₂ = ( 20000 - 2000 ) / 1000

       = ( 18,000 ) / 1000

       = 18.0 m/s east  

Hence we can conclude that the final velocity of the car after the Impulse is applied is 18.0 m/s east.

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the answer is b ) square root of 5

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.