How many calories of heat must you remove if you want to lower the temperature of 350 g of steel from 18.0 °c to 12.0 °c? the specific heat of steel is 0.11 cal/g °
c.?

Heat to be removed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
Heat = 350(0.11)(12.0 - 18.0)
Heat = -231 cal 

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)