12 m solution of nacl in water has a freezing point which differs from that of pure water by 0.4c. state the expected freezing difference for each of the following solutions in water: 0.06m nacl, 0.12 m nabr, ).12 m na3po4

This process is freezing point depression. Freezing-point depression is the process in which adding a solute to a solvent decreases the freezing point of the solvent. Examples include salt in water, alcohol in water, or the mixing of two solids such as impurities in a finely powdered drug. and it is a function of the number of electrolyte formed
for 0.06 M NaCl since is half of the 0.12 M NaCl so the difference is 0.2 C
for 0.12 M NaBr it will also form 2 electrolye so the difference is also 0.4 C
for 0.12 M Na3PO4 since it will form 4 electrolyte so the difference would be 0.8 C

The answer would be a