Pulling a wheel with a string? a bicycle wheel is mounted on a fixed, frictionless axle, with a light string wound around its rim. the wheel has moment of inertia i = k m r^2, where m is its mass, r is its radius, and k is a dimensionless constant between zero and one. the wheel is rotating counterclockwise with angular velocity omega_0, when

A)♣ the string being pulled, 
the angular speed is: w1=w0 +w’*t, hence t=(w1-w0)/w’; 
the angular path is: b=w0*t+0.5*w’*t^2, where angular acceleration 
w’=T/J, torq T=F*r, and b*r=L; 
♦ thus b=w0*(w1-w0)/w’ +0.5*w’*((w1-w0)/w’)^2 = 
= (w1-w0)*(w0 +0.5w1 -0.5w0)/w’ =0.5*(w1^2 –w0^2)/w’; 
♠ and b=L/r =0.5*(w1^2 –w0^2)/(F*r/J); 
2(F*r/J)*L/r =w1^2 –w0^2, hence 
w1^2=2F*L/J +w0^2; 
b)♣ the power is P=F*(w0*r);

Thank you for posting your question here at . I hope the answer will help you. Feel free to ask more questions.

By dividing you can find the answer

It indicates no change in temperature and the process of matter changing its state