Bob is pulling a 30kg filing cabinet with a force of 200n , but the filing cabinet refuses to move. the coefficient of static friction between the filing cabinet and the floor is 0.80.
what is the magnitude of the friction force on the filing cabinet?
express your answer to two significant figures and include the appropriate units.

By making a free-body diagram in a vertical direction, the normal force is given by:

Fn = m * g

Where,

m: mass

g: acceleration of gravity.

Then, the friction force is given by:

F = μ * Fn

Where,

μ: friction coefficient

Substituting values we have:

F = μ * m * g

F = 0.80 * 30 * 9.8

F = 235 N

We note that the friction force (235 N) is greater than the 200 N force with which Bob pushes the sled.

Therefore, the sled will not move.

The magnitude of the friction force on the filing cabinet is:

F = 235 N

the device is called “ rocket engine”