Manipulate the following equation to solve for t: s=1/2 at^2

Explanation:

It is given by :

..... (1)

Where

s = distance covered

a = acceleration of an object

t = time taken

We need to manipulate given equation to find the value of t. On cross multiplication to both side of equation (1) we get:

Dividing both side of above equation by a we get :

Taking square root of above equation we get :

So, the value of t is, . Hence, this is the required solution.

0.11 m/s and 0.28 m/s should be correct

i'm on my way to history not a mistory.