Abaseball player is stealing second base when he goes into a slide, which gives him an acceleration of −2.5 m/s2. if he had an initial speed of 7 m/s, how far does he slide before coming to a complete stop?

The distance is 9.8 m.

Explanation:

Given that,

Acceleration = -2.5 m/s²

Initial speed = 7 m/s

We need to calculate the time

Using equation of motion

Where, v = final velocity

u = initial velocity

t = time

a = acceleration

Put the value into the formula

We need to calculate the distance

Using equation of motion

Hence, The distance is 9.8 m.

the body's situation won't change the forces are equal opposit and on the same body