The volume of an ideal gas is decreased from 5.0 l to 5.0 ml at a constant pressure of 2.0 atm. calculate the work associated with this process

The work is 9.99J.

Explanation:

The work associated with a process is given by the following formula:

In which W is the work, P is the pressure and is the difference of volume.

In this problem, we have that:

The volume of an ideal gas is decreased from 5.0 l to 5.0 ml. Each ml has 0.001l. So the volume of the ideal gas is decreased from 5.0l to 0.005l. So

.

Constant pressure of 2.0 atm. So .

The work is 9.99J.

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

scientific laws are the result of testing theories and proving them to be facts.